GEN 13B : Triangle of velocity, HDG, Track Drift

 

Results

Q1. The distance A to B is 90 NM in a straight line. You are 60 NM from A when you fix your position 4 NM to the left of track. What correction do you need to make to arrive at B?

12° –

  • Track Error = 4°. Closing Angle = 8°. Total correction = 12°.

    • Q2. You are flying 090°(C) heading. Deviation is 2W and Variation is 12E. Your TAS is 160 knots. You are flying the 070 radial outbound from a VOR and you have gone 14 NM in 6 minutes. What is the W/V?

    158°(T)/51 –

  • True Heading 100°. Track 082°. GS 140. Wind from SE (158) explains the drift and headwind.

    • Q3. Given: True course 300° Drift 8°R Variation 10°W Deviation -4° Calculate the compass heading.

    306° –

  • TH = 292°. MH = 302°. CH = 306°.

    • Q4. How many nautical miles are travelled in 1 minute 45 seconds at a ground speed of 135 knots?

    3.94 –

  • 1.75 minutes at 135 kts = 3.94 NM.

    • Q5. TAS=240 knots. Track is 180°(T) The relative bearing from an NDB is 315(R) at 1410. At 1420 the bearing has changed to 270(R). What is your distance from the NDB at 1420?

    40 NM –

  • Bearing change from -45° to -90° (beam) implies distance to station equals distance flown (10 mins @ 240 kts = 40 NM).

    • Q6. Course 040°(T), TAS 120 kt, Wind speed = 30 knots. From which direction will the wind give the greatest drift?

    245°(T) –

  • Greatest drift occurs with wind perpendicular to track (Beam wind at 130/310). 245° is closest to the beam axis.

    • Q7. Given the following: True track: 192′ Magnetic variation: 7ºE Drift angle: 5″ left What is the magnetic heading required to maintain the given track?

    Q8. Given the following: Magnetic heading: 060′ Magnetic variation: 8OW Drift angle: 4′ right, what is the true track?

    Q9. An aircraft is following a true track of 048′ at a constant TAS of 210 kt. The wind velocity is 350′ / 30 kt. The GS and drift angle are?

    Q10. For a given track the: Wind component = +45 kt Drift angle = 15′ left TAS = 240 kt What is the wind component on the reverse track?

    Q11. Given: iMagnetic heading = 255′ VAR = 40°W GS = 375 kt WIV = 235′(T) I 120 kt Calculate the drift angle?

    Q12. Given: True Heading = 180′ TAS = 500 kt WIV 225′ I 100 kt Calculate the GS?

    Q13. Given: True heading = 310′ TAS = 200 kt GS = 176 kt Drift angle 7′ right. Calculate the WIV?

    Q14. Given: True Heading = 090′ TAS = 180 kt GS = 180 kt Drift 5′ right Calculate the W/V?

    Q15. Given: True Heading = 090′ TAS = 200 kt WN = 220′ / 30 kt. Calculate the GS?

    Q16. An aeroplane is flying at TAS 180 kt on a track of 090′. The W/V is 045′ / 50kt. How far can the aeroplane fly out from its base and return in one hour?

    Q17. The following information is displayed on an Inertial Navigation System: GS 520 kt, True HDG 090°, Drift angle 5′ right, TAS 480 kt. SAT (static air temperature) -51°C. The W/V being experienced is?

    Q18. The reported surface wind from the Control Tower is 240/35 kt. Runway 30 (300′). What is the cross-wind component?

    Q19. Given: M 0.80, OAT -50°C, FL 330, GS 490 kt, VAR 20°W, Magnetic heading 140°, Drift is 11 Right. Calculate the true W/V?

    Q20. Given: Compass Heading 090°, Deviation 2W, Variation 12E, TAS 160 kt. Whilst maintaining a radial 070′ from a VOR station, the aircraft flies a ground distance of 14 NM in 6 MIN. What is the WV (T)?

    Q21. Given: true track is 348, drift 17′ left, variation 32′ W, deviation 4’E. What is the compass heading?

    Q22. Given: TAS = 220 kt; Magnetic course = 212 “, WlV 160 “(M)/ 50kt, Calculate the GS?

    Q23. Given: TAS = 250 kt; Magnetic course = 212 “, W/V 160 “(M)/ 50kt, Calculate the GS?

    Q24. Given: TAS = 270 kt, True HDG = 270°, Actual wind 205º(T)/30kt, Calculate the drift angle and GS?

    Q25. Given: TAS = 125 kt, True HDG = 35S0, WIV = 320°(T)/30kt. Calculate the true track and GS?

    Q26. Given: TAS = 198 kt, HDG (ºT) = 180, WIV = 359/25. Calculate the Track(ºT) and GS?

    Q27. Given: TAS = 170 kt, HDG(T) = 100°, W/V = 350/30kt. Calculate the Track (ºT) and GS?

    Q28. Given: TAS = 235 kt, HDG (T) = 076º WV = 040/40kt. Calculate the drift angle and GS?

    Q29. Given: TAS = 465 kt, HDG (T) = 124º, WV = 170/80kt. Calculate the drift and GS?

    Q30. Given: TAS = 190 kt, HDG (T) = 355º, W/V = 165/25kt. Calculate the drift and GS ?

    Q31. Given: True HDG = 307º, TAS = 230 kt, Track (T) = 313º, GS = 210 kt. Calculate the WV

    Q32. Given: True HDG = 145º, TAS = 240 kt, Track (T) = 150°, GS = 210 kt. Calculate the W/V?

    Q33. Given: True HDG = 002º, TAS = 130 kt, Track (T) = 353º, GS = 132 kt. Calculate the W/V?

    Q34. Given: True HDG = 035º, TAS = 245 kt, Track (T) = 046º, GS = 220 kt. Calculate the W/V?

    Q35. Given: course required = 085º (T)? Forecast W/V 030/100kt, TAS = 470 kt, Distance = 265 NM. Calculate the true HDG and flight time?

    Q36. Given: Maximum allowable tailwind component for landing 10 kt. Planned runway 05 (047º magnetic). The direction of the surface wind reported by ATIS 210º. Variation is 17ºE. Calculate the maximum allowable windspeed that can be accepted without exceeding the tailwind limit?

    Q37. Given: Runway direction 083º(M), Surface W/V 035/35kt. Calculate the effective headwind component?

    Q38. Given: Course 040°(T), TAS is 120 kt, Wind speed 30 kt. Maximum drift angle will be obtained for a wind direction of:

    Q39. Given: Course 095º(T), TAS is 220 kt, Wind speed 70 kt. Maximum drift angle will be obtained for a wind direction of:

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